In Home Décor departments of which cities were the sales amounts the highest in 2018 and 2019, respectively?
Solution
Home Décor highest: Delhi in 2018 (80) and Delhi in 2019 (100).
5 sets, 24 questions, in exam order.
A chain of departmental stores has outlets in Delhi, Mumbai, Bengaluru and Kolkata. The sales are categorized by its three departments - ‘Apparel’, ‘Electronics’, and ‘Home Décor’. An Accountant has been asked to prepare a summary of the 2018 and 2019 sales amounts for an internal report. He has collated partial information and prepared the following table.

The following additional information is known.
1. The sales amounts in the Apparel departments were the same for Delhi and Kolkata in 2018.
2. The sales amounts in the Apparel departments were the same for Mumbai and Bengaluru in 2018. This sales amount matched the sales amount in the Apparel department for Delhi in 2019.
3. The sales amounts in the Home Décor departments were the same for Mumbai and Kolkata in 2018.
4. The sum of the sales amounts of four Electronics departments increased by the same amount as the sum of the sales amounts of four Apparel departments from 2018 to 2019.
5. The total sales amounts of the four Home Décor departments increased by Rs 70 Crores from 2018 to 2019.
6. The sales amounts in the Home Décor departments of Delhi and Bengaluru each increased by Rs 20 Crores from 2018 to 2019.
7. The sales amounts in the Apparel departments of Delhi and Bengaluru each increased by the same amount in 2019 from 2018. The sales amounts in the Apparel departments of Mumbai and Kolkata also each increased by the same amount in 2019 from 2018.
8. The sales amounts in the Apparel departments of Delhi, Kolkata and Bengaluru in 2019 followed an Arithmetic Progression.
Electronics rose from 330 to 370 (+40), so Apparel also rose by 40 in total.
Apparel 2018: Delhi Kolkata , Mumbai Bengaluru Delhi 2019. Delhi and Bengaluru rise by , Mumbai and Kolkata by , with .
; Kolkata 2019: . AP (Delhi, Kolkata, Bengaluru 2019): .
Solving: , , , .
Home Décor: 2019 total 306, so 2018 total 236. Delhi 80, Bengaluru 60, and Mumbai Kolkata .
| Dept | Delhi | Mumbai | Bengaluru | Kolkata |
|---|---|---|---|---|
| Apparel | 42 → 50 | 50 → 62 | 50 → 58 | 42 → 54 |
| Electronics | 78 → 98 | 82 → 102 | 90 → 70 | 80 → 100 |
| Home Décor | 80 → 100 | 48 → 72 | 60 → 80 | 48 → 54 |
In Home Décor departments of which cities were the sales amounts the highest in 2018 and 2019, respectively?
Home Décor highest: Delhi in 2018 (80) and Delhi in 2019 (100).
What was the increase in sales amount, in Crore Rupees, in the Apparel department of Mumbai from 2018 to 2019?
.
Among all the 12 departments (i.e., the 3 departments in each of the 4 cities), what was the maximum percentage increase in sales amount from 2018 to 2019?
Mumbai Home Décor: , i.e. , the largest rise.
What was the total sales amount, in Crore Rupees, in 2019 for the chain of departmental stores?
Apparel 224 Electronics 370 Home Décor 306 .
In an election several candidates contested for a constituency. In any constituency, the winning candidate was the one who polled the highest number of votes, the first runner up was the one who polled the second highest number of votes, the second runner up was the one who polled the third highest number of votes, and so on. There were no ties (in terms of number of votes polled by the candidates) in any of the constituencies in this election. In an electoral system, a security deposit is the sum of money that a candidate is required to pay to the election commission before he or she is permitted to contest. Only the defeated candidates (i.e., one who is not the winning candidate) who fail to secure more than one sixth of the valid votes polled in the constituency, lose their security deposits.
The following table provides some incomplete information about votes polled in four constituencies: A, B, C and D, in this election .

The following additional facts are known:
1. The first runner up polled 10,000 more votes than the second runner up in constituency A.
2. None of the candidates who contested in constituency C lost their security deposit. The difference in votes polled by any pair of candidates in this constituency was at least 10,000.
3. The winning candidate in constituency D polled 5% of valid votes more than that of the first runner up. All the candidates who lost their security deposits while contesting for this constituency, put together, polled 35% of the valid votes.
A candidate loses the deposit with at most of the valid votes.
A: of 5,00,000 . Second runner-up has (keeps it). The other 7 share , all losing.
B: the winner has only 48,750, below of 3,25,000 (), so all 11 losers lose deposits (2,76,250 votes).
C: each loser has more than 1,00,005, so at least 1,00,006, and gaps are at least 10,000. Minimum for the four losers: , leaving the winner at most 1,40,006; but the winner must exceed the top loser by 10,000, so at least 1,40,006. Winner , runner-up 1,30,006.
D: with : winner ; top three ; the rest , and each is below while the second runner-up (30,000) is above. It fits.
What is the percentage of votes polled in total by all the candidates who lost their security deposits while contesting for constituency A?
.
How many candidates who contested in constituency B lost their security deposit?
All losers.
What BEST can be concluded about the number of votes polled by the winning candidate in constituency C?
.
What was the number of valid votes polled in constituency D?
.
The winning margin of a constituency is defined as the difference of votes polled by the winner and that of the first runner up. Which of the following CANNOT be the list of constituencies, in increasing order of winning margin?
Margins: A 1,80,000; C 10,000; D 8,750; B anywhere from 1 up to about 23,600. D is always below C, so B, C, D, A is impossible.
For all the four constituencies taken together, what was the approximate number of votes polled by all the candidates who lost their security deposit expressed as a percentage of the total valid votes from these four constituencies?
Lost deposits: . Total valid: 16,00,030. .
Twenty five coloured beads are to be arranged in a grid comprising of five rows and five columns. Each cell in the grid must contain exactly one bead. Each bead is coloured either Red, Blue or Green. While arranging the beads along any of the five rows or along any of the five columns, the rules given below are to be followed:
1. Two adjacent beads along the same row or column are always of different colours.
2. There is at least one Green bead between any two Blue beads along the same row or column.
3. There is at least one Blue and at least one Green bead between any two Red beads along the same row or column.
Every unique, complete arrangement of twenty five beads is called a configuration.
In any row or column: neighbours differ, two Blues need a Green between them, and two Reds need both a Blue and a Green between them.
So two Reds in a line are at least 3 apart: a line of 5 holds at most 2 Reds, at positions 1 & 4, 1 & 5 or 2 & 5, never in the middle.
Example with 9 Reds:
| R | B | G | R | B |
|---|---|---|---|---|
| G | R | B | G | R |
| B | G | R | B | G |
| R | B | G | R | B |
| G | R | B | G | R |
The total number of possible configurations using beads of only two colours is:
Red with one other colour fails (Reds need both B and G between them). Blue and Green alternate in a checkerboard, in ways.
What is the maximum possible number of Red beads that can appear in any configuration?
10 Reds would need exactly 2 in every row, and a row with 2 Reds has none in column 3, leaving column 3 empty of Reds, a contradiction. 9 is achievable (example above).
What is the minimum number of Blue beads in any configuration?
Without a Blue, a row alternates Red and Green and two Reds would have no Blue between them, so every row needs a Blue (at least 5). Checking shows 5 is impossible; 6 works, e.g. rows RBGRG, BGRGB, GRGBG, RGBGR, GBGRG.
Two Red beads have been placed in ‘second row, third column’ and ‘third row, second column’. How many more Red beads can be placed so as to maximise the number of Red beads used in the configuration?
With Reds fixed at (2, 3) and (3, 2), the maximum is 8 Reds, so more.
The Humanities department of a college is planning to organize eight seminars, one for each of the eight doctoral students - A, B, C, D, E, F, G and H. Four of them are from Economics, three from Sociology and one from Anthropology department. Each student is guided by one among P, Q, R, S and T. Two students are guided by each of P, R and T, while one student is guided by each of Q and S. Each student is guided by a guide belonging to their department. Each seminar is to be scheduled in one of four consecutive 30-minute slots starting at 9:00 am, 9:30 am, 10:00 am and 10:30 am on the same day. More than one seminars can be scheduled in a slot, provided the guide is free. Only three rooms are available and hence at the most three seminars can be scheduled in a slot. Students who are guided by the same guide must be scheduled in consecutive slots.
The following additional facts are also known.
1. Seminars by students from Economics are scheduled in each of the four slots.
2. A’s is the only seminar that is scheduled at 10:00 am. A is guided by R.
3. F is an Anthropology student whose seminar is scheduled at 10:30 am.
4. The seminar of a Sociology student is scheduled at 9:00 am.
5. B and G are both Sociology students, whose seminars are scheduled in the same slot. The seminar of an Economics student, who is guided by T, is also scheduled in the same slot.
6. P, who is guiding both B and C, has students scheduled in the first two slots.
7. A and G are scheduled in two consecutive slots.
P guides B (Sociology) and C, so P is a Sociology guide and C is Sociology too. Sociology: B, C, G. F (Anthropology) and G each have a single-student guide (Q or S). Economics: A, D, E, H, guided by R (A and one more) and T (two).
G is next to A's 10:00 slot. 10:30 already has F, so B, G, F and a T student would be 4. Hence B, G and an Economics T student are at 9:30.
P's students fill the first two slots: C at 9:00 (the 9:00 Sociology seminar).
T's students are consecutive: the other one is at 9:00 (10:00 has only A). R's other student is at 10:30 (9:30 is full).
| Slot | Seminars |
|---|---|
| 9:00 | C (P), Econ (T) |
| 9:30 | B (P), G (Q/S), Econ (T) |
| 10:00 | A (R) |
| 10:30 | F (Q/S), Econ (R) |
D, E, H fill the three Economics places.
Which one of the following statements is true?
Two seminars at 9:00.
Who all are NOT guiding any Economics students?
Economics guides are R and T. P, Q and S guide none.
Which of the following statements is necessarily true?
D, E, H are all Economics.
If D is scheduled in a slot later than Q's, then which of the following two statement(s) is(are) true?
(i) E and H are guided by T.
(ii) G is guided by Q.
Q's student is at 9:30 (G) or 10:30 (F). D is later than Q's slot only if Q guides G and D is the R student at 10:30. Then E and H are T's. Both true.
If E and Q are both scheduled in the same slot, then which of the following statements BEST describes the relationship between D, H, and T?
If Q guides G, E is a T student at 9:30 and exactly one of D, H is the other T. If Q guides F, E is the R student at 10:30 and both D, H are T's. At least one of D, H is with T.
If D is scheduled in the slot immediately before Q’s, then which of the following is NOT necessarily true?
D right before Q's slot: Q guides G (9:30) and D is at 9:00 with T; so S guides F. E can be at 9:30 (T) or 10:30 (R), so "E is guided by R" isn't necessary.
A shopping mall has a large basement parking lot with parking slots painted in it along a single row. These slots are quite narrow; a compact car can fit in a single slot but an SUV requires two slots. When a car arrives, the parking attendant guides the car to the first available slot from the beginning of the row into which the car can fit.
For our purpose, cars are numbered according to the order in which they arrive at the lot. For example, the first car to arrive is given a number 1, the second a number 2, and so on. This numbering does not indicate whether a car is a compact or an SUV. The configuration of a parking lot is a sequence of the car numbers in each slot. Each single vacant slot is represented by letter V.
For instance, suppose cars numbered 1 through 5 arrive and park, where cars 1, 3 and 5 are compact cars and 2 and 4 are SUVs. At this point, the parking lot would be described by the sequence 1, 2, 3, 4, 5. If cars 2 and 5 now vacate their slots, the parking lot would now be described as 1, V, V, 3, 4. If a compact car (numbered 6) arrives subsequently followed by an SUV (numbered 7), the parking lot would be described by the sequence 1, 6, V, 3, 4, 7.
Answer the following questions INDEPENDENTLY of each other.
Each car takes the first gap from the start that fits it (1 slot for a compact, 2 for an SUV).
Initially cars numbered 1, 2, 3, and 4 arrive among which 1 and 4 are SUVs while 2 and 3 are compact cars. Car 1 then leaves, followed by the arrivals of car 5 (a compact car) and car 6 (an SUV). Car 4 then leaves. Then car 7 (an SUV) and car 8 (a compact car) arrive. At this moment, which among the following numbered car is parked next to car 3?
1 (SUV, slots 1–2), 2 (3), 3 (4), 4 (SUV, 5–6). Car 1 leaves; 5 takes slot 1; 6 (SUV) goes to 7–8. Car 4 leaves; 7 (SUV) takes 5–6; 8 takes slot 2.
Row: 5, 8, 2, 3, 7, 6. Car 3's neighbours are 2 and 7.
Suppose eight cars have arrived, of which two have left. Also suppose that car 4 is a compact and car 7 is an SUV. Which of the following is a POSSIBLE current configuration of the parking lot?
Option D works: cars 1–6 compact park in order, 7 (SUV) after them. Cars 1 and 4 leave; car 8 takes slot 1, leaving slot 4 vacant: 8, 2, 3, V, 5, 6, 7.
In the other options a later car sits ahead of an earlier one in a gap that the earlier car would have taken first.
Suppose the sequence at some point of time is 4, 5, 6, V, 3. Which of the following is NOT necessarily true?
The space before car 3 was held by cars 1 and 2 (at most 4 slots). It now holds 4, 5, 6 and one V, so it is exactly 4 slots: 1 and 2 were SUVs and 4, 5, 6 are compacts. Car 3's size is not fixed.
Suppose that car 4 is not the first car to leave and that the sequence at a time between the arrival of the car 7 and car 8 is V, 7, 3, 6, 5. Then which of the following statements MUST be false?
Car 6 now sits where car 4 was, so 6 arrived after 4 left, and someone (1 or 2) left before 4. That gap near the front was free when 6 arrived. A compact 6 would have parked there, so car 6 being a compact must be false.
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