A machine depreciates by 20% every year. Its value after 2 years is Rs. 32,000. What was its original value?
Solution
Value after 2 years = V × (4/5)^2.
V = 32,000 ÷ 16/25 = 50,000.
Answer: (D) Rs. 50,000
Quantitative Aptitude · Arithmetic
Percentages: MAH CET, NMAT and SNAP practice questions
20 questions in the pattern of MAH MBA CET, NMAT and SNAP. Each question is marked with the exams it suits. Answer it, then open the step-by-step solution.
Exam:
In an election between two candidates, 20% of the 6000 votes were invalid. The winner got 60% of the valid votes. How many votes did the loser get?
Solution
Valid = 80% of 6000 = 4800.
Loser = 40% of 4800 = 1920.
Answer: (B) 1920
Successive discounts of 20%, 25% and 15% are equivalent to a single discount of:
Solution
Price after the discounts = 80% × 75% × 85% = 51% of the original.
Single discount = 100 − 51 = 49%.
Answer: (B) 49%
If A's income is 20% more than B's, by what percentage is B's income less than A's?
Solution
Take the smaller as 100; the larger is 120.
Less by 20/120 × 100 = 16 2/3%.
Answer: (A) 16 2/3%
If Ravi's income is 20% more than Mohan's, by what percentage is Mohan's income less than Ravi's?
Solution
Take the smaller as 100; the larger is 120.
Less by 20/120 × 100 = 16 2/3%.
Answer: (D) 16 2/3%
In an examination, 29% of the students failed in English, 24% failed in Maths and 7% failed in both. If 540 students passed in both subjects, how many students appeared?
Solution
Failed in at least one = 29 + 24 − 7 = 46%, so 54% passed both.
54% of N = 540, so N = 1000.
Answer: (B) 1000
If 12% of x equals 45% of y, what is x : y?
Solution
12x/100 = 45y/100, so x/y = 45/12 = 15/4.
Answer: (D) 15 : 4
In an examination, 24% of the students failed in English, 10% failed in Maths and 9% failed in both. What percentage passed in both subjects?
Solution
Failed in at least one = 24 + 10 − 9 = 25%.
Passed in both = 100 − 25 = 75%.
Answer: (A) 75%
In a school of 1000 students, 70% are boys. 65% of the boys and 85% of the girls passed an exam. What percentage of all students passed?
Solution
Boys = 700, girls = 300. Passed = 455 + 255 = 710.
Percentage = 710/1000 × 100 = 71%.
Answer: (B) 71%
The population of a town is 10,000. It increases by 20% in the first year and decreases by 10% in the second year. What is the population after two years?
Solution
After 2 years = 10,000 × 1.2 × 9/10 = 10,800.
Answer: (C) 10,800
A 25% fall in the price of sugar lets a buyer get 5 kg more for Rs. 800. What is the reduced price per kg?
Solution
The 25% saving on Rs. 800 is Rs. 200, and it buys the extra 5 kg at the new price.
Reduced price = 200/5 = 40 per kg.
Answer: (A) Rs. 40
The population of a town is 25,000. It decreases by 20% in the first year and increases by 25% in the second year. What is the population after two years?
Solution
After 2 years = 25,000 × 4/5 × 1.25 = 25,000.
Answer: (A) 25,000
The price of an article is increased by 50% and then decreased by 30%. What is the net percentage change?
Solution
Net change = x + y + xy/100 = 50 + (-30) + (50 × -30)/100 = 5%.
Answer: (C) 5% increase
In an election between two candidates, 20% of the 8000 votes were invalid. The winner got 65% of the valid votes. How many votes did the loser get?
Solution
Valid = 80% of 8000 = 6400.
Loser = 35% of 6400 = 2240.
Answer: (A) 2240
A 20% rise in the price of rice forces a family to buy 5 kg less for Rs. 900. What was the original price per kg?
Solution
At the new price, 20% of Rs. 900 = Rs. 180 is exactly the cost of the 5 kg given up, so the new price = 180/5 = 36.
Original price = 36 × 100/120 = 30.
Answer: (A) Rs. 30
The price of an article is decreased by 20% and then decreased by 25%. What is the net percentage change?
Solution
Net change = x + y + xy/100 = -20 + (-25) + (-20 × -25)/100 = -40%.
Answer: (D) 40% decrease
A machine depreciates by 25% every year. Its value after 2 years is Rs. 45,000. What was its original value?
Solution
Value after 2 years = V × (3/4)^2.
V = 45,000 ÷ 9/16 = 80,000.
Answer: (C) Rs. 80,000
A number is increased by 20% and the result is decreased by 20%. The final value is 576. What was the original number?
Solution
Final = N × 1.2 × 4/5 = 24/25N.
N = 576 ÷ 24/25 = 600.
Answer: (C) 600
If 40% of x equals 15% of y, what is x : y?
Solution
40x/100 = 15y/100, so x/y = 15/40 = 3/8.
Answer: (A) 3 : 8
Raj spends 25% of his salary on rent, 40% of the rest on food and 20% of what remains on travel. He saves Rs. 10,800. What is his salary?
Solution
Savings = S × 3/4 × 3/5 × 4/5 = 9/25S.
S = 10,800 ÷ 9/25 = 30000.
Answer: (D) Rs. 30,000
These are original practice questions written by Target Campus in the pattern and difficulty of MAH MBA CET, NMAT, SNAP and other MBA entrance tests. They are not previous-year papers.
Preparing for MAH CET, SNAP or NMAT? Courses, live classes and mocks by Dr. Kiran Derle at Target Campus.
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