How many factors does 48 have?
Solution
48 = 2^4 × 3.
Number of factors = product of (power + 1) = 5 × 2 = 10.
20 questions in the pattern of MAH MBA CET, NMAT and SNAP. Each question is marked with the exams it suits. Answer it, then open the step-by-step solution.
How many factors does 48 have?
48 = 2^4 × 3.
Number of factors = product of (power + 1) = 5 × 2 = 10.
What is the unit digit of 23^367?
Unit digits of powers of 23 repeat every 4: 3, 9, 7, 1.
367 = 4 × 91 + 3, so the unit digit matches 23^3: 7.
What is the unit digit of 4^48 × 9^97 × 3^40?
Unit digits: 4^48 → 6, 9^97 → 9, 3^40 → 1 (using cycles of 4).
6 × 9 × 1 ends in 4.
What is the 39th term of the series 7, 17, 27, …?
First term 7, common difference 10.
T39 = 7 + (39 − 1) × 10 = 387.
Simplify: 200 ÷ 8 × 5 − 20 + 60 ÷ 5
Using BODMAS, do ÷ and × from left to right first: 200 ÷ 8 = 25; 25 × 5 = 125; 60 ÷ 5 = 12.
Then 125 − 20 + 12 = 117.
The sum of the digits of a two-digit number is 13. When the digits are reversed, the number decreases by 9. What is the number?
Let the number be 10a + b with a + b = 13.
Reversing changes it by 9|a − b| = 9, so |a − b| = 1.
Since it decreases, the tens digit is larger: a = 7, b = 6. Number = 76.
How many numbers from 19 to 847 (both included) are divisible by 3 or 8?
Divisible by 3: 276. By 8: 103. By both (by 24): 35.
Answer = 276 + 103 − 35 = 344.
What is the remainder when 5^288 is divided by 7?
5^6 leaves remainder 1 when divided by 7, so powers repeat every 6.
288 = 6 × 48 + 0, so the remainder equals that of 5^0 = 1, which is 1.
How many zeros are there at the end of 323! ?
Each trailing zero needs a factor 10 = 2 × 5, and 5s are fewer than 2s.
Number of 5s = 64 + 12 + 2 = 78.
How many factors does 120 have?
120 = 2^3 × 3 × 5.
Number of factors = product of (power + 1) = 4 × 2 × 2 = 16.
Which of the following numbers between 88 and 128 is a prime number?
101 has no factor other than 1 and itself (check primes up to √101 ≈ 10).
121 = 11 × 11.
119 = 7 × 17.
123 = 3 × 41.
What is the largest 4-digit number exactly divisible by 24?
The largest 4-digit number is 9999. 9999 ÷ 24 leaves remainder 15.
9999 − 15 = 9984.
What is the remainder when 3^330 is divided by 7?
3^6 leaves remainder 1 when divided by 7, so powers repeat every 6.
330 = 6 × 55 + 0, so the remainder equals that of 3^0 = 1, which is 1.
The sum of 3 consecutive even numbers is 114. What is the largest of them?
Let the smallest be x: x + (x + 2) + (x + 4) = 114.
3x + 6 = 114, so x = 36.
Largest = 40.
A number when divided by 144 leaves a remainder of 68. What will be the remainder when the same number is divided by 12?
The number = 144k + 68. Since 144 = 12 × 12, 144k is divisible by 12.
So the remainder is 68 mod 12 = 8.
What is the unit digit of 7^25 × 4^37 × 9^70?
Unit digits: 7^25 → 7, 4^37 → 4, 9^70 → 1 (using cycles of 4).
7 × 4 × 1 ends in 8.
What is the difference between the place value and the face value of 2 in 429215?
Face value of 2 = 2. Place value = 2 × 10000 = 20000.
Difference = 20000 − 2 = 19998.
A number when divided by 144 leaves a remainder of 27. What will be the remainder when the same number is divided by 12?
The number = 144k + 27. Since 144 = 12 × 12, 144k is divisible by 12.
So the remainder is 27 mod 12 = 3.
How many zeros are there at the end of 63! ?
Each trailing zero needs a factor 10 = 2 × 5, and 5s are fewer than 2s.
Number of 5s = 12 + 2 = 14.
What is the unit digit of 47^473?
Unit digits of powers of 47 repeat every 4: 7, 9, 3, 1.
473 = 4 × 118 + 1, so the unit digit matches 47^1: 7.
These are original practice questions written by Target Campus in the pattern and difficulty of MAH MBA CET, NMAT, SNAP and other MBA entrance tests. They are not previous-year papers.
Preparing for MAH CET, SNAP or NMAT? Courses, live classes and mocks by Dr. Kiran Derle at Target Campus.
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