Technical · Mechanical Engineering
Strength of Materials MCQs for placement tests
20 technical questions of moderate difficulty, as asked in campus placement and company tests. Each has a short explanation.
Q1Mechanical · Strength of MaterialsModerate
Solution
σ = F/A.
Answer: (C) Force per unit area
Q2Mechanical · Strength of MaterialsModerate
Solution
Strain is a ratio of lengths.
Answer: (D) A dimensionless quantity
Q3Mechanical · Strength of MaterialsModerate
Hooke's law states that, within the elastic limit, stress is proportional to:
Solution
σ = E × ε.
Answer: (C) Strain
Q4Mechanical · Strength of MaterialsModerate
A steel rod of area 100 mm² carries a load of 20 kN. The stress is:
Solution
σ = 20,000 N / 100 mm² = 200 N/mm².
Answer: (D) 200 N/mm²
Q5Mechanical · Strength of MaterialsModerate
Poisson's ratio is the ratio of:
Solution
ν = −lateral strain / longitudinal strain.
Answer: (B) Lateral strain to longitudinal strain
Q6Mechanical · Strength of MaterialsModerate
The value of Poisson's ratio for most metals is about:
Solution
Steel is about 0.3.
Answer: (B) 0.25 to 0.35
Q7Mechanical · Strength of MaterialsModerate
For a simply supported beam with a central point load W and span L, the maximum bending moment is:
Solution
Each support carries W/2; at mid-span M = (W/2)(L/2).
Answer: (B) WL/4
Q8Mechanical · Strength of MaterialsModerate
For a simply supported beam with a uniformly distributed load w per metre over span L, the maximum bending moment is:
Solution
It occurs at mid-span.
Answer: (B) wL²/8
Q9Mechanical · Strength of MaterialsModerate
For a cantilever of length L with a point load W at the free end, the maximum bending moment is:
Solution
Moment is greatest at the fixed support.
Answer: (B) WL at the fixed end
Q10Mechanical · Strength of MaterialsModerate
Bending stress in a beam is maximum at:
Solution
σ = My/I, largest where y is largest.
Answer: (C) The outermost fibres
Q11Mechanical · Strength of MaterialsModerate
The section modulus Z is equal to:
Solution
Z = I/y_max, and σ_max = M/Z.
Answer: (A) I / y_max
Q12Mechanical · Strength of MaterialsModerate
The moment of inertia of a rectangular section of width b and depth d about its centroidal axis parallel to b is:
Solution
I = bd³/12.
Answer: (B) bd³/12
Q13Mechanical · Strength of MaterialsModerate
Shear force is zero at a section where the bending moment is:
Solution
dM/dx = V, so V = 0 at an extreme of M.
Answer: (C) Maximum or minimum
Q14Mechanical · Strength of MaterialsModerate
The point where the bending moment changes sign is called:
Solution
Curvature changes direction there.
Answer: (C) The point of contraflexure
Q15Mechanical · Strength of MaterialsModerate
For a solid circular shaft, the polar moment of inertia is:
Solution
J = πd⁴/32.
Answer: (B) πd⁴/32
Q16Mechanical · Strength of MaterialsModerate
Euler's formula for buckling applies to:
Solution
Short columns fail by crushing rather than buckling.
Answer: (A) Long columns
Q17Mechanical · Strength of MaterialsModerate
The effective length of a column fixed at both ends is:
Solution
Both ends fixed give Le = 0.5L.
Answer: (D) L/2
Q18Mechanical · Strength of MaterialsModerate
The effective length of a column fixed at one end and free at the other is:
Solution
A cantilever column has Le = 2L.
Answer: (C) 2L
Q19Mechanical · Strength of MaterialsModerate
The ratio of ultimate stress to working stress is called the:
Solution
It gives a margin against failure.
Answer: (C) Factor of safety
Q20Mechanical · Strength of MaterialsModerate
A thin cylinder under internal pressure p (diameter d, thickness t) has hoop stress:
Solution
Hoop stress is pd/2t; longitudinal stress is pd/4t.
Answer: (C) pd/2t