Rs. 720 is divided among A, B and C in the ratio 3 : 7 : 2. What is C's share?
Solution
Total parts = 3 + 7 + 2 = 12; one part = 720/12 = 60.
C's share = 2 × 60 = 120.
30 moderate questions in the pattern of campus placement tests. Pick an option to check your answer, then open the step-by-step solution.
Rs. 720 is divided among A, B and C in the ratio 3 : 7 : 2. What is C's share?
Total parts = 3 + 7 + 2 = 12; one part = 720/12 = 60.
C's share = 2 × 60 = 120.
If A : B = 5 : 2 and B : C = 7 : 4, what is A : B : C?
Make B the same in both: A : B = 35 : 14 and B : C = 14 : 8.
So A : B : C = 35 : 14 : 8 = 35 : 14 : 8.
A bag has one-rupee, 50-paise and 25-paise coins in the ratio 4 : 2 : 3. The total value is Rs. 172.50. How many 50-paise coins are there?
Let the counts be 4x, 2x, 3x. Value = 4x + 2x/2 + 3x/4 = 23x/4.
23x/4 = 172.5 gives x = 30.
50-paise coins = 2 × 30 = 60.
What is the mean proportional between 9 and 25?
Mean proportional = √(9 × 25) = √225 = 15.
Rs. 2160 is divided among A, B and C in the ratio 8 : 7 : 3. What is C's share?
Total parts = 8 + 7 + 3 = 18; one part = 2160/18 = 120.
C's share = 3 × 120 = 360.
If A : B = 2 : 4 and B : C = 3 : 6, what is A : B : C?
Make B the same in both: A : B = 6 : 12 and B : C = 12 : 24.
So A : B : C = 6 : 12 : 24 = 1 : 2 : 4.
A bag has one-rupee, 50-paise and 25-paise coins in the ratio 2 : 1 : 3. The total value is Rs. 87.75. How many 50-paise coins are there?
Let the counts be 2x, 1x, 3x. Value = 2x + 1x/2 + 3x/4 = 13x/4.
13x/4 = 87.75 gives x = 27.
50-paise coins = 1 × 27 = 27.
What is the mean proportional between 9 and 81?
Mean proportional = √(9 × 81) = √729 = 27.
Rs. 1200 is divided among A, B and C in the ratio 2 : 4 : 6. What is C's share?
Total parts = 2 + 4 + 6 = 12; one part = 1200/12 = 100.
C's share = 6 × 100 = 600.
If A : B = 5 : 3 and B : C = 2 : 2, what is A : B : C?
Make B the same in both: A : B = 10 : 6 and B : C = 6 : 6.
So A : B : C = 10 : 6 : 6 = 5 : 3 : 3.
A bag has one-rupee, 50-paise and 25-paise coins in the ratio 1 : 4 : 5. The total value is Rs. 76.50. How many 50-paise coins are there?
Let the counts be 1x, 4x, 5x. Value = 1x + 4x/2 + 5x/4 = 17x/4.
17x/4 = 76.5 gives x = 18.
50-paise coins = 4 × 18 = 72.
What is the mean proportional between 9 and 4?
Mean proportional = √(9 × 4) = √36 = 6.
Rs. 840 is divided among A, B and C in the ratio 4 : 3 : 7. What is C's share?
Total parts = 4 + 3 + 7 = 14; one part = 840/14 = 60.
C's share = 7 × 60 = 420.
If A : B = 7 : 9 and B : C = 4 : 2, what is A : B : C?
Make B the same in both: A : B = 28 : 36 and B : C = 36 : 18.
So A : B : C = 28 : 36 : 18 = 14 : 18 : 9.
A bag has one-rupee, 50-paise and 25-paise coins in the ratio 2 : 1 : 4. The total value is Rs. 52.50. How many 50-paise coins are there?
Let the counts be 2x, 1x, 4x. Value = 2x + 1x/2 + 4x/4 = 14x/4.
14x/4 = 52.5 gives x = 15.
50-paise coins = 1 × 15 = 15.
What is the mean proportional between 25 and 16?
Mean proportional = √(25 × 16) = √400 = 20.
Rs. 1200 is divided among A, B and C in the ratio 3 : 8 : 4. What is C's share?
Total parts = 3 + 8 + 4 = 15; one part = 1200/15 = 80.
C's share = 4 × 80 = 320.
If A : B = 6 : 4 and B : C = 7 : 7, what is A : B : C?
Make B the same in both: A : B = 42 : 28 and B : C = 28 : 28.
So A : B : C = 42 : 28 : 28 = 3 : 2 : 2.
A bag has one-rupee, 50-paise and 25-paise coins in the ratio 4 : 5 : 3. The total value is Rs. 130.50. How many 50-paise coins are there?
Let the counts be 4x, 5x, 3x. Value = 4x + 5x/2 + 3x/4 = 29x/4.
29x/4 = 130.5 gives x = 18.
50-paise coins = 5 × 18 = 90.
What is the mean proportional between 25 and 100?
Mean proportional = √(25 × 100) = √2500 = 50.
Rs. 1200 is divided among A, B and C in the ratio 5 : 3 : 7. What is C's share?
Total parts = 5 + 3 + 7 = 15; one part = 1200/15 = 80.
C's share = 7 × 80 = 560.
If A : B = 7 : 9 and B : C = 6 : 7, what is A : B : C?
Make B the same in both: A : B = 42 : 54 and B : C = 54 : 63.
So A : B : C = 42 : 54 : 63 = 14 : 18 : 21.
What is the fourth proportional to 7, 3 and 14?
If 7 : 3 = 14 : x, then x = 3 × 14 / 7 = 6.
Two numbers are in the ratio 7 : 5. If 8 is added to each, the ratio becomes 25 : 19. What is the larger number?
Let the numbers be 7k and 5k. (7k + 8) : (5k + 8) = 25 : 19.
Solving gives k = 6, so the numbers are 42 and 30. Larger = 42.
A bag has one-rupee, 50-paise and 25-paise coins in the ratio 3 : 5 : 1. The total value is Rs. 155.25. How many 50-paise coins are there?
Let the counts be 3x, 5x, 1x. Value = 3x + 5x/2 + 1x/4 = 23x/4.
23x/4 = 155.25 gives x = 27.
50-paise coins = 5 × 27 = 135.
What is the mean proportional between 25 and 64?
Mean proportional = √(25 × 64) = √1600 = 40.
Two numbers are in the ratio 3 : 7. If 6 is added to each, the ratio becomes 15 : 31. What is the larger number?
Let the numbers be 3k and 7k. (3k + 6) : (7k + 6) = 15 : 31.
Solving gives k = 8, so the numbers are 24 and 56. Larger = 56.
What is the fourth proportional to 8, 5 and 8?
If 8 : 5 = 8 : x, then x = 5 × 8 / 8 = 5.
Two numbers are in the ratio 7 : 5. If 6 is added to each, the ratio becomes 55 : 41. What is the larger number?
Let the numbers be 7k and 5k. (7k + 6) : (5k + 6) = 55 : 41.
Solving gives k = 7, so the numbers are 49 and 35. Larger = 49.
Two numbers are in the ratio 2 : 5. If 2 is added to each, the ratio becomes 3 : 7. What is the larger number?
Let the numbers be 2k and 5k. (2k + 2) : (5k + 2) = 3 : 7.
Solving gives k = 8, so the numbers are 16 and 40. Larger = 40.
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